What is the distance between #(7, 4)# and #(5, 2) #?

1 Answer
Jun 13, 2017

Answer:

#2sqrt2~~2.828" to 3 dec. places"#

Explanation:

#"to calculate the distance (d) use the "color(blue)"distance formula"#

#color(red)(bar(ul(|color(white)(2/2)color(black)(d=sqrt((x_2-x_1)^2+(y_2-y_1)^2))color(white)(2/2)|)))#
where # (x_1,y_1),(x_2,y_2)" are 2 coordinate points"#

#"the points are " (x_1,y_1)=(7,4),(x_2,y_2)=(5,2)#

#"substituting into the formula gives"#

#d=sqrt((5-7)^2+(2-4)^2)#

#color(white)(d)=sqrt(4+4)#

#color(white)(d)=sqrt8#

#color(white)(d)=sqrt(4xx2)=sqrt4xxsqrt2#

#color(white)(d)=2sqrt2~~2.828" to 3 decimal places"#