What is the distance between # (–7, 8) # and # (3, 5) #?

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Answer 1 · 2015-12-06T14:12:58

#sqrt109#

The distance between 2 points #(x1,y1) and (x2,y2)#=#sqrt((x2-x1)^2+(y2-y1)^2)#

So the distance between #(-7,8) and (3,5)#=#sqrt((3+7)^2+(5-8)^2)#
=#sqrt109#

Answer 2 · 2015-12-06T14:22:45

#sqrt(109)#

enter image source here
By the Pythagorean Theorem
distance between the given points is
#color(white)("XXX")sqrt(10^2+3^2) = sqrt(109)#