Question

What is the distance between `(–7, 8)` and # (3,7) #?

Answer 1

`sqrt(101)`

Explanation:

In general: distance between two points `(x_1,y_1)` and `(x_2,y_2)` is `sqrt((x_2-x_1)^2+(y_2-y_1)^2`

Therefore by inserting `x_1` as -7, `y_1` as 8, `x_2` as 3 and `y_2` as 7:

Distance = `sqrt((3--7)^2+(7-8))^2`
Distance = `sqrt(10^2+(-1)^2)`
Distance = `sqrt(100+1)`
Distance = `sqrt(101)`