# What is the distance between (8,0,6) and (1,-4,5)?

Jan 5, 2016

$d = \sqrt{66}$

#### Explanation:

Distance in 3D is just pythagoras, except you now have a term for the z coordinates.

${d}^{2} = {\left(8 - 1\right)}^{2} + {\left(0 + 4\right)}^{2} + {\left(6 - 5\right)}^{2}$
${d}^{2} = {\left(7\right)}^{2} + {\left(4\right)}^{2} + {\left(1\right)}^{2}$
${d}^{2} = 49 + 16 + 1$
${d}^{2} = 66$
$d = \sqrt{66}$