# What is the distance between (8, 2)  and  (4, 7) ?

Dec 29, 2015

Its $\sqrt{41}$

#### Explanation:

We first need to calculate the difference in x axis and in y axis:
$\triangle x = 8 - 4 = 4$
$\triangle y = 7 - 2 = 5$
Having this values, we now have a triangle rectangle with angles in both points. Now, just apply Pythagoras' formula:
${\text{line}}^{2} = \triangle {x}^{2} + \triangle {y}^{2}$
${\text{line}}^{2} = {4}^{2} + {5}^{2}$
$\text{line} = \sqrt{41}$