What is the distance between (8, 6, 0)  and (0, 4, –2) ?

Feb 19, 2016

$6 \sqrt{2}$
Distance formula = sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2
$D = \sqrt{{\left(8 - 0\right)}^{2} + {\left(6 - 4\right)}^{2} + {\left(0 - - 2\right)}^{2}}$
$= \sqrt{64 + 4 + 4} = \sqrt{72} = 6 \sqrt{2}$