# What is the distance between (8, 6, 2)  and  (4, 3, 1) ?

Feb 28, 2016

$\sqrt{26}$

#### Explanation:

Using the distance formula for 3-D space viz

$d = \sqrt{{\left({x}_{2} - {x}_{1}\right)}^{2} + {\left({y}_{2} - {y}_{1}\right)}^{2} + {\left({z}_{2} - {z}_{1}\right)}^{2}}$

Where

$\left({x}_{1} , {y}_{1} , {z}_{1}\right)$ = (8, 6, 2)

$\left({x}_{2} , {y}_{2} , {z}_{2}\right)$ = (4, 3, 1)

Substitute in distance formula