# What is the distance between (-8,8,-1) and (3,1,2)?

Nov 7, 2016

The distance is $\sqrt{179}$
If you have two points $\left({x}_{1} , {y}_{1} , {z}_{1}\right)$ and $\left({x}_{2} , {y}_{2} , {z}_{2}\right)$
The distance is $= \sqrt{{\left({x}_{2} - {x}_{1}\right)}^{2} + {\left({y}_{1} - {y}_{2}\right)}^{2} + {\left({z}_{1} - {z}_{2}\right)}^{2}}$
The distance is $= \sqrt{{11}^{2} + {7}^{2} + {3}^{2}} = \sqrt{121 + 49 + 9} = \sqrt{179}$