# What is the distance between (9,0,1) and (1,-4,-2)?

$d = \sqrt{89} = 9.434 \text{ }$units

#### Explanation:

The distance formula $\left(9 , 0 , 1\right)$ and $\left(1 , - 4 , - 2\right)$

$d = \sqrt{{\left({x}_{2} - {x}_{1}\right)}^{2} + {\left({y}_{2} - {y}_{1}\right)}^{2} + {\left({z}_{2} - {z}_{1}\right)}^{2}}$

$d = \sqrt{{\left(9 - 1\right)}^{2} + {\left(0 - - 4\right)}^{2} + {\left(1 - - 2\right)}^{2}}$

d=sqrt((8^2+4^2+3^2)
$d = \sqrt{64 + 16 + 9}$
$d = \sqrt{89}$

God bless....I hope the explanation is useful.