# What is the distance between (9, 2, 0)  and (6, 8, 2) ?

Dist. is $7$.
The dist. $d$ btwn. pts. $A \left({x}_{1} , {y}_{1} , {z}_{1}\right) \mathmr{and} B \left({x}_{2} , {y}_{2} , {z}_{2}\right)$, is given by,
$d = \sqrt{{\left({x}_{1} - {x}_{2}\right)}^{2} + {\left({y}_{1} - {y}_{2}\right)}^{\circ} + {\left({z}_{1} - {z}_{2}\right)}^{2}}$
Hence, $d = \sqrt{9 + 36 + 4} = 7$.