What is the distance between #(9, 2, 0) # and #(8, 6, 2) #?
1 Answer
Mar 30, 2017
Explanation:
The distance formula for 3 dimensions is:
#sqrt((Deltax)^2 + (Deltay)^2 + (Deltaz)^2)#
In this case,
#Deltax = 8 - 9 = -1#
#Deltay = 6 - 2 = 4#
#Deltaz = 2 - 0 = 2#
So the distance is:
#sqrt((-1)^2 + 4^2 + 2^2) = sqrt(1+16+4) = sqrt21#
