# What is the distance between (9, 2, 0)  and (8, 6, 2) ?

Mar 30, 2017

$\sqrt{21}$

#### Explanation:

The distance formula for 3 dimensions is:

$\sqrt{{\left(\Delta x\right)}^{2} + {\left(\Delta y\right)}^{2} + {\left(\Delta z\right)}^{2}}$

In this case,

$\Delta x = 8 - 9 = - 1$
$\Delta y = 6 - 2 = 4$
$\Delta z = 2 - 0 = 2$

So the distance is:

$\sqrt{{\left(- 1\right)}^{2} + {4}^{2} + {2}^{2}} = \sqrt{1 + 16 + 4} = \sqrt{21}$