# What is the distance between #(9, 2, 0) # and #(8, 6, 2) #?

##### 1 Answer

Mar 30, 2017

#### Explanation:

The distance formula for 3 dimensions is:

#sqrt((Deltax)^2 + (Deltay)^2 + (Deltaz)^2)#

In this case,

#Deltax = 8 - 9 = -1#

#Deltay = 6 - 2 = 4#

#Deltaz = 2 - 0 = 2#

So the distance is:

#sqrt((-1)^2 + 4^2 + 2^2) = sqrt(1+16+4) = sqrt21#