# What is the distance between P(12, 4) and Q(-8, 2)?

Jun 5, 2016

It is $20.1$.

#### Explanation:

The distance of two points of coordinates $\left({x}_{1} , {y}_{1}\right)$ and $\left({x}_{2} , {y}_{2}\right)$ is

$d = \sqrt{{\left({x}_{1} - {x}_{2}\right)}^{2} + {\left({y}_{1} - {y}_{2}\right)}^{2}}$

in our case

$d = \sqrt{{\left(12 - \left(- 8\right)\right)}^{2} + {\left(4 - 2\right)}^{2}}$

$d = \sqrt{{20}^{2} + {2}^{2}}$

$d = \sqrt{404}$

$d \setminus \approx 20.1$.