# What is the distance between P(–2, 1, 3) and point Q(–1, 4, –2)?

Nov 7, 2016

#### Answer:

The distance $P Q = \sqrt{35}$

#### Explanation:

We can do it using vectors.
vec(PQ)=〈-1,4,-2〉-〈-2,1,3〉=〈1,3,-5〉
The distance $P Q$ is equal to the modulus of $\vec{P Q}$
$= | | \vec{P Q} | | = \sqrt{1 + 9 + 25} = \sqrt{35}$