What is the distance between P(4,1) and Q(12,-5)?

Mar 18, 2016

$\text{distance="10" } u n i t$

Explanation:

$P \left(x , y\right) \text{ } Q \left(a , b\right)$
"distance="sqrt((a-x)^2+(b-y)^2
"distance:"=sqrt((12-4)^2+(-5-1)^2
$\text{distance=} \sqrt{{8}^{2} + {\left(- 6\right)}^{2}}$
$\text{distance=} \sqrt{64 + 36}$
$\text{distance=} \sqrt{100}$
$\text{distance="10" } u n i t$