Question

What is the distance of (1,-3) and (4,3)?

Answer 1

`3sqrt5`

Explanation:

Distance between two point equation is:

`sqrt((x_2-x_1)^2+(y_2-y_1)^2`

Take `(1,-3)` as `(x_1, y_1)`
Take `(4,3)` as `(x_2, y_2)`

Substitute into equation:

`sqrt((4-1)^2+(3--3)^2`

Simplify to get `3sqrt5`

Answer 2

`sqrt45~~6.708" to 3 dec. places"`

Explanation:

`"using the "color(blue)"distance formula"`

`•color(white)(x)d=sqrt((x_2-x_1)^2+(y_2-y_1)^2)`

`"let "(x_1,y_1)=(1,-3)" and "(x_2,y_2)=(4,3)`

`d=sqrt((4-1)^2+(3-(-3))^2)`

`color(white)(d)=sqrt(9+36)=sqrt45~~6.708`