What is the distance of (1,-3) and (4,3)?

2 Answers
Apr 19, 2018

Answer:

#3sqrt5#

Explanation:

Distance between two point equation is:

#sqrt((x_2-x_1)^2+(y_2-y_1)^2#

Take #(1,-3)# as #(x_1, y_1)#
Take #(4,3)# as #(x_2, y_2)#

Substitute into equation:

#sqrt((4-1)^2+(3--3)^2#

Simplify to get #3sqrt5#

Apr 19, 2018

Answer:

#sqrt45~~6.708" to 3 dec. places"#

Explanation:

#"using the "color(blue)"distance formula"#

#•color(white)(x)d=sqrt((x_2-x_1)^2+(y_2-y_1)^2)#

#"let "(x_1,y_1)=(1,-3)" and "(x_2,y_2)=(4,3)#

#d=sqrt((4-1)^2+(3-(-3))^2)#

#color(white)(d)=sqrt(9+36)=sqrt45~~6.708#