What is the domain and range of # f(t) = root3(3) sqrt (6t − 2)#?

1 Answer
Nov 10, 2017

Answer:

Domain: # t>=1/3 or [1/3 ,oo)#
Range : # f(t) >=0 or [0,oo)#

Explanation:

#f(t) = root(3) 3 sqrt (6t-2)# Domain: Under root #>=0# otherwise

#f(t)# will be undefined. #:. 6t-2 >=0 or t>=1/3#.

Domain: # t>=1/3 or [1/3 ,oo)# . Range will not be any negatve

number , so Range : # f(t) >=0 or [0,oo)#

graph{3^(1/3)*sqrt(6x-2) [-20, 20, -10, 10]}