# What is the domain and range of y =sqrt(17x+8)?

Domain: $x \ge - \frac{8}{17}$ or Domain:$\left[- \frac{8}{17} , + \infty\right)$
Range:$y \ge 0$ or Range:$\left[0 , + \infty\right)$

#### Explanation:

The square root of a negative number is an imaginary number.
The square root of zero is zero. The radicand is zero at $x = - \frac{8}{17}$.
Any value greater than -8/17 will result to a positive radicand.
Therefore, Domain: $x \ge - \frac{8}{17}$

Range: is 0 to +infinity

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