# What is the electric current produced when a voltage of 9 V is applied to a circuit with a resistance of 90 Omega?

If we apply voltage $V$ across a resistor whose resistance is $R$ then the current $I$ flowing across it can be calculated by
$I = \frac{V}{R}$
Here we are applying voltage of $9 V$ across a $90 \Omega$ resistor, therefore, the current flowing is
$I = \frac{9}{90} = 0.1$ $\implies I = 0.1 A$
Hence, the electric current produced is $0.1 A$.