What is the equation for the function that passes through the points (1, 3/2) and (3/2, 2)?

1 Answer
Oct 22, 2017

Let's have a look.

Explanation:

Let the function or more specifically, the line be a function of both x & y.

Now, equation of a straight line passing through the points (x_1,y_1) & (x_2,y_2) be rarr

color(red)(y-y_1=m(x-x_1)).

where, m is the slope of the line.

color(red)(m=(y_2-y_1)/(x_2-x_1))

Now, substituting the points given in the above equations, we get rarr

color(red)(y-3/2=((2-3/2)/(3/2-1))xx(x-1)).

Now, simplify the equation to get the desired one.

Hope it Helps:)