What is the equation of a line parallel to the line y = 3x + 2, passing through the point (10,1)?

1 Answer
Mar 5, 2018

y=3x-29

Explanation:

First, let's find the slope of the line y=3x+2
As the equation is already in slope-intercept form y=mx+c,

Slope = 3

Let a point (x,y) be on the new line.
By finding the slope again,

(y-1)/(x-10)=3

y-1=3(x-10)

y-1=3x-30

Which can then be converted to different forms:

Standard form: 3x-y=29
Equation form: 3x-y-29=0
Slope-intercept form: y=3x-29

graph{3x-y=29 [-32.3, 47.7, -34.1, 5.9]}