What is the equation of the axis of symmetry and the coordinates of the vertex of the graph of the function #y=4x^2-8x-3#?

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Answer 1 · 2016-11-13T17:25:06

The the equation for the axis of symmetry is #x = 1#

The vertex is #(1, -7)#

For a parabola with an equation of the form:

#y = ax^2 + bx + c#

The equation for the line of the axis of symmetry is:

#x = h#

And the vertex is:

#(h,k)#

Where:

#h = (-b)/(2a) = - (-8)/(2(4)) = 1#

and:

#k = a(h)^2 + b(h) + c = 4(1)^2 - 8(1) - 3 = -7#

The the equation for the axis of symmetry is #x = 1#

The vertex is #(1, -7)#