What is the equation of the circle with a center at (3 ,1 ) and a radius of 2 ?
1 Answer
Jan 26, 2016
Explanation:
The standard form of a circle with a center at
(x-h)^2+(y-k)^2=r^2
Since the center is
{(h=3),(k=1),(r=2):}
Thus, the equation of the circle is
(x-3)^2+(y-1)^2=2^2
This simplifies to be
(x-3)^2+(y-1)^2=4