What is the equation of the circle with a center at (3 ,1 ) and a radius of 2 ?

1 Answer
Jan 26, 2016

(x-3)^2+(y-1)^2=4

Explanation:

The standard form of a circle with a center at (h,k) and a radius r is

(x-h)^2+(y-k)^2=r^2

Since the center is (3,1) and the radius is 2, we know that

{(h=3),(k=1),(r=2):}

Thus, the equation of the circle is

(x-3)^2+(y-1)^2=2^2

This simplifies to be

(x-3)^2+(y-1)^2=4