What is the equation of the circle with a center at (3 ,5 ) and a radius of 1 ?

1 Answer
Jan 26, 2016

(x-3)^2+(y-5)^2=1

Explanation:

The standard form of a circle with a center at (h,k) and a radius r is

(x-h)^2+(y-k)^2=r^2

Since the center is (3,5) and the radius is 1, we know that

{(h=3),(k=5),(r=1):}

Thus, the equation of the circle is

(x-3)^2+(y-5)^2=1^2

This simplifies to be

(x-3)^2+(y-5)^2=1