Question

What is the equation of the line between `(-20,2)` and `(7,-8)`?

Answer 1

The equation of the line in standard form is `10x +27y = -146`

Explanation:

The slope of the line passing through `(-20,2) and (7,-8)` is `m= (y_2-y_1)/(x_2-x_1)= (-8-2)/(7+20)=-10/27`

Let the equation of the line in slope-intercept form be `y=mx+c or y=-10/27x+c` The point (-20,2) will satisfy the equation . So, `2= -10/27*(-20)+c or c= 2-200/27= -146/27`

Hence the equation of the line in slope-intercept form is `y= -10/27x-146/27.`

The equation of the line in standard form is `y= -10/27x-146/27. or 27y =-10x-146 or 10x +27y = -146` {Ans]