What is the equation of the line between #(3,-2)# and #(-23,11)#?

1 Answer
May 19, 2018

#y=-1/2x-1/2#

Explanation:

The formula for a linear graph is #y=mx+b# . To solve this problem, you have to find the #m#-value first. To do this, use the slope formula:

(#(y_1-y_2)/(x_1-x_2)#)

For this formula you will use the two points that are given; (3, -2) and (-23, 11):

(#(11-(-2))/((-23)-3)# = #-13/26# = #-1/2# →Slope

After finding the slope, you have to find the #b#-value. To do that, you will plug in the new slope and one of the given points:

#y=-1/2x+b#
#-2=-1/2(3)+b#
#-2=-3/2+b#
#+3/2# To both sides
#-1/2=b#

After finding the #b# and #m#-value, plug them into the form #y=mx+b# and you have your answer:

#y=-1/2x-1/2#