# What is the equation of the line perpendicular to y=-3/7x  that passes through  (8,5) ?

##### 1 Answer
Apr 13, 2018

y = $\frac{7}{3} x - \frac{41}{3}$

#### Explanation:

For perpendicular lines, the product of their slopes is -1
The slope of the line is $- \frac{3}{7}$
Hence, the slope of the line perpendicular is ( $- \frac{1}{- \frac{3}{7}}$) = $\frac{7}{3}$
$y - y 1 = m \left(x - x 1\right)$
y-5 = $\frac{7}{3}$(x - 8)
y = $\frac{7}{3} x - \frac{56}{3} + 5$
y = $\frac{7}{3} x - \frac{41}{3}$