# What is the equation of the line perpendicular to #y=-9/16x # that passes through # (-12,5) #?

##### 1 Answer

Apr 9, 2016

#y=16/9x+79/3#

#### Explanation:

The given line is

#y=(-9)/16x#

Two Lines are perpendicular if

Where -

#m_1: # slope of the given line

#m_2: # slope of the required line

Then

#m_2=-1 xx 16/(-9)=16/9#

The equation of the required line is -

#y-y_1=m_2(x-x_1)#

#y-5=16/9(x-(-12))#

#y=16/9x+12(16/9)+5#

#y=16/9x+79/3#