# What is the equation of the line that is perpendicular to the line passing through #(3,18)# and #(-5,12)# at midpoint of the two points?

##### 2 Answers

#### Answer:

#### Explanation:

There could be two ways.

**One** - The midpoint of

The slope of line joining

Hence, slope of line perpendicular to it will be

**Two** - A line which is perpendicular to line joining

#### Answer:

#### Explanation:

The Mid-point M of the segment joining

Slope of Line

Therefore, the slope of the line

Thus, the reqd. line has slope

Using, the **Slope-Point Form** , the reqd. line is :

# y-15=-4/3(x+1), i.e., 3y-45+4x+4=0, or,