What is the equation of the line that is perpendicular to the line passing through #(3,18)# and #(-5,12)# at midpoint of the two points?
There could be two ways.
One - The midpoint of
The slope of line joining
Hence, slope of line perpendicular to it will be
Two - A line which is perpendicular to line joining
The Mid-point M of the segment joining
Slope of Line
Therefore, the slope of the line
Thus, the reqd. line has slope
Using, the Slope-Point Form , the reqd. line is :
# y-15=-4/3(x+1), i.e., 3y-45+4x+4=0, or,