Question

What is the equation of the line that passes through points `(\frac { 1} { 2} ,\frac { 1} { 3} ) and ( \frac { 1} { 14} ,\frac { 11} { 14} )`?

Answer 1

`y+19/18x-31/36=0`

Explanation:

Finding the slope
`m=(y_2-y_1)/(x_2-x_1)`

`=((11/14)-(1/3))/((1/14)-(1/2))=(-19)/18`

Now, using the point slope formula with point `(1/2, 1/3)`,
`y-y_1=m(x-x_1)`

`y-(1/3)=(-19)/18(x-1/2)`

`y+19/18x+(-1/3-19/36)=0`

`y+19/18x-31/36=0`... Check it out here
graph{y+19/18x-31/36=0 [-10, 10, -5, 5]}