What is the equation of the line that passes through the point (4,-5) and is parallel to 2x-5y= -10?

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Answer 1 · 2018-04-03T12:02:43

The equation of line passing through #(4,-5)# , parallal to
#2x-5y=-10# is #2x-5y=33#

Parallal lines have equal slopes . Therefore the equation of a line

parallal to #2x-5y=-10;(1)# is #2x-5y+c=0 ; (2)# The point

#(4,-5)# is on the line so , it will satisfy the equation (2).

# :. 2*4-5*(-5)+c=0 or 8+25+c=0 :. c=-33#

So , the equation the line is #2x-5y-33=0 or 2x-5y=33#

The equation of line passing through #(4,-5)# , parallal to

#2x-5y=-10# is #2x-5y=33 # [Ans]