# What is the equation of the line with slope  m= -13/5  that passes through  (-23,4) ?

$13 x + 5 y = - 279$

#### Explanation:

Given $m = - \frac{13}{5}$
${P}_{1} \left({x}_{1} , {y}_{1}\right) = \left(- 23 , 4\right)$

Using the Point-Slope Form

$y - {y}_{1} = m \left(x - {x}_{1}\right)$

$y - 4 = - \frac{13}{5} \left(x - - 23\right)$

$y - 4 = - \frac{13}{5} \left(x + 23\right)$

$5 \left(y - 4\right) = 5 \left(- \frac{13}{5}\right) \left(x + 23\right)$

$5 y - 20 = - 13 \left(x + 23\right)$

$5 y - 20 = - 13 x - 299$

$13 x + 5 y = - 279$

God bless....I hope the explanation is useful.