Question

What is the equation of the line with slope `m= -13/5` that passes through `(-23,4)`?

Answer 1

`13x+5y=-279`

Explanation:

Given `m=-13/5`
`P_1(x_1, y_1)=(-23, 4)`

Using the Point-Slope Form

`y-y_1=m(x-x_1)`

`y-4=-13/5(x--23)`

`y-4=-13/5(x+23)`

`5(y-4)=5(-13/5)(x+23)`

`5y-20=-13(x+23)`

`5y-20=-13x-299`

`13x+5y=-279`

God bless....I hope the explanation is useful.