What is the equation of the tangent line to the polar curve #f(theta)=theta- sin((3theta)/2-pi/2)+tan((2theta)/3-pi/2) # at #theta = pi#?
Let's begin by determining the
The point through which the line must pass is:
This reference Tangents to polar curves gives us an equation for
To obtain the slope of the tangent line, m, we evaluate the above at
Therefore, we need to evaluate
Using the point-slope form of the equation of a line: