What is the factors for $4x^2 -9$ ?

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Answer 1 · 2015-05-06T04:46:47

$4x^2 - 9 = (2x)^2 - 3^2$

We know that $color(blue)(a^2 - b^2 = (a+b)(a-b)$

Hence $(2x)^2 - 3^2 = (2x + 3)(2x - 3)$

The factors of $4x^2 - 9$ are $color(green)((2x + 3)$ and $color(green)((2x - 3)$

Answer 2 · 2015-05-06T04:47:17

The answer is $(4x^2-9)=(2x-3)(2x+3)$ .

This is an example of the difference of squares, where $(a^2-b^2)=(a-b)(a+b)$ .

$(4x^2-9)=((2x)^2-3^2)$

$a=2x$
$b=3$

$(4x^2-9)=(2x-3)(2x+3)$

What is the factors for 4x^2 -94x^2 -9?