What is the factors for #6x² + 8x + 2#? Algebra Polynomials and Factoring Factoring Completely 1 Answer bp May 18, 2015 Factors are 2(3x+1)(x+1) #6x^2 +8x+2# = #2(3x^2 +4x +1)# =#2(3x^2 +3x+x+1)# =#2[3x(x+1) +(x+1)]# = 2 (3x+1)(x+1) Answer link Related questions What is Factoring Completely? How do you know when you have completely factored a polynomial? Which methods of factoring do you use to factor completely? How do you factor completely #2x^2-8#? Which method do you use to factor #3x(x-1)+4(x-1) #? What are the factors of #12x^3+12x^2+3x#? How do you find the two numbers by using the factoring method, if one number is seven more than... How do you factor #12c^2-75# completely? How do you factor #x^6-26x^3-27#? How do you factor #100x^2+180x+81#? See all questions in Factoring Completely Impact of this question 1394 views around the world You can reuse this answer Creative Commons License