# What is the force, in terms of Coulomb's constant, between two electrical charges of -25 C and 60 C that are 15 m  apart?

Dec 22, 2015

$6.667 k$ newtons

#### Explanation:

Coulomb's Law states that the electrostatic force between 2 point charges is directly proportional to the product of the 2 charges and inversely proportional to the square of the distance between them.
ie. $F = k \frac{{Q}_{1} {Q}_{2}}{r} ^ 2$,
where $k = 9 \times {10}^{9} N . {m}^{2} / k {g}^{2}$ is Coulomb's Constant.

So, in terms of Coulomb's constant, this particular force will be

$F = k \frac{25 \times 60}{{15}^{2}}$

$= 6.667 k$ newtons

Note also that this force will be attraction since it is unlike charges.