# What is the frequency of f(theta)= sin 2 t - cos 12 t ?

Feb 5, 2017

$\frac{1}{\pi}$

#### Explanation:

The period $\frac{2 \pi}{2} = \pi$ of $\sin 2 t$ is

$6 \times$(the period $\frac{2 \pi}{12} = \frac{\pi}{6}$) of $\cos 12 t$.

So, the period for the compounded oscillation

$f \left(t\right) = \sin 2 t - \cos 12 t$ is $\pi$.

The frequency = 1/(period)=$\frac{1}{\pi}$.