What is the ground-state electron configuration of a neutral atom of fluorine?

1 Answer
May 30, 2018

Well, for fluorine, $Z = 9$...and so we have to distribute NINE electrons according to the $\text{Aufbau scheme...}$

Explanation:

And so for ATOMIC fluorine...

$1 {s}^{2} 2 {s}^{2} 2 {p}^{5}$....and such a configuration rationalizes why fluorine such a powerful oxidant....the addition of a single gives a complete electronic shell. Elemental fluorine is certainly the most reactive element on the Periodic Table. Of course, when it is used preparatively (and used carefully by specialists), we gots the ${F}_{2}$ molecule....