# What is the inverse of y = log_2 (2x + 1)  ?

Jan 27, 2016

$x = \frac{{2}^{y} - 1}{2}$

#### Explanation:

$y = {\log}_{2} \left(2 x + 1\right)$

${2}^{y} = 2 x + 1$

$2 x = {2}^{y} - 1$

$x = \frac{{2}^{y} - 1}{2}$