What is the kinetic energy of an object with a mass of #1 kg# that has been in freefall for #1 s#?

1 Answer
Feb 17, 2016

Answer:

#48.02# Joules

Explanation:

Kinetic energy (#KE#) is given by #(m.v^2)/2#, where #m# is mass in kg and #v# is velocity in meters. As the object of mass #1# kg undergoes free fall for #1# second, its velocity at the end of one second is given by #v=g*t#, where #g# is #9.8# #m/s^2# i.e.

#v=9.8*1=9.8# #m/s#, and hence #KE# is given by

#1/2*9.8^2 = 48.02# Joules.