Question

What is the kinetic energy of an object with a mass of `3 kg` that has been in freefall for `14 s`?

Answer 1

`=28235.76 J`

Explanation:

if the velocity gained after 14s free fall be v starting with an initial velocity u =0, falling with acceleration g = 9.8`ms^-2`
then
`v=u+g*t=0+9.8*14= 137.2ms^-1`
Hence KE =`1/2mv^2=1/2*3*(137.2)^2=28235.76 J`