# What is the kinetic energy of an object with a mass of 3 kg that has been in freefall for 14 s?

$= 28235.76 J$
if the velocity gained after 14s free fall be v starting with an initial velocity u =0, falling with acceleration g = 9.8$m {s}^{-} 2$
$v = u + g \cdot t = 0 + 9.8 \cdot 14 = 137.2 m {s}^{-} 1$
Hence KE =$\frac{1}{2} m {v}^{2} = \frac{1}{2} \cdot 3 \cdot {\left(137.2\right)}^{2} = 28235.76 J$