What is the limit as #x# approaches infinity of #sinx#? Precalculus Limits Limits Involving Infinity 1 Answer Shura Jun 6, 2015 The range of #y = sinx# is #R = [-1;+1]#; the function oscillates between -1 and +1. Therefore, the limit when #x# approaches infinity is undefined. Answer link Related questions How do I find the limit as #x# approaches infinity of #(1.001)^x#? How do I find the limit as #x# approaches infinity of #x^7/(7x)#? How do I find the limit as #x# approaches infinity of #xsin(1/x)#? How do I find the limit as #x# approaches infinity of the square root function? How do I find the limit as #x# approaches infinity of #tanx#? What is the limit as #x# approaches infinity of #(x^2-4)/(2x-4x^2)#? What is the limit as #x# approaches infinity of #1/x#? What is the limit as #x# approaches infinity of #x#? What is the limit as #x# approaches infinity of #cosx#? What is the limit as #x# approaches infinity of #lnx#? See all questions in Limits Involving Infinity Impact of this question 35394 views around the world You can reuse this answer Creative Commons License