# What is the mass of a sample of gold that occupies 0.56 cm^3?

## The density of gold is $19.3$ $g$$/ c {m}^{3}$.

Sep 20, 2016

$\text{Mass}$ $\cong 10 - 11 \cdot g$

#### Explanation:

$\text{Density, } \rho$ $=$ $\text{Mass"/"Volume}$.

Thus $\text{Mass"=rhoxx"volume}$

$=$ $19.3 \cdot g \cdot \cancel{c {m}^{-} 3} \times 0.56 \cdot \cancel{c {m}^{3}}$ $\cong 10 - 11 \cdot g$.

This calculation is consistent dimensionally. I wanted a mass of gold, and the units cancelled to give an answer in grams, i.e. units of mass, which is a good check that I have multiplied correctly; it's all too easy to make a mistake.

Gold is worth approx \$42.38*USD*g^-1. How much is your nugget worth?