# What is the maximum amount of silver (in grams) that can be plated out of 5.0 L of an AgNO_3 solution containing 3.6% Ag by mass? Assume that the density of the solution is 1.01 g/mL?

Under $200 \cdot g$
$\text{Mass of solution}$ $=$ $5.0 \cdot \cancel{L} \times {10}^{3} \cdot \cancel{m L} \cdot \cancel{{L}^{-} 1} \times 1.01 \cdot g \cdot \cancel{m {L}^{-} 1}$ $=$ $5050 \cdot g$
If silver ion concentration is 3.6%(m/m), then this corresponds to 5050*gxx3.6%=??*g of silver ion.