# What is the molar mass of Ca_5(PO_4)_3(OH)?

##### 1 Answer
Jan 7, 2016

$502 g / m o l$

#### Explanation:

To find the molar mass, we add the molar mass of each atom each time it occurs in the compound.
The individual molar masses may be looked up on the periodic table.

$5 C a + 3 P + 13 O + 1 H \implies \left(5 \times 40\right) + \left(3 \times 31\right) + \left(13 \times 16\right) + \left(1 \times 1\right)$

$= 200 + 93 + 208 + 1$

$= 502$.

This means that 1 mole ($6.023 \times {10}^{23}$ particles) of the given compound will have a mass of $502$ grams.