# What is the molar mass of H_3PO_4?

$97.995 g / m o l$
$M \left({H}_{3} P {O}_{4}\right) = 3 \times M \left(H\right) + M \left(P\right) + 4 \times M \left(O\right)$
$= 3 \times 1.008 + 30.9738 + 4 \times 15.9994 = 97.995 g / m o l$