# What is the molecular geometry, or shape, of chloroform CHCl_3?

Jul 16, 2017

Tetrahedral Parent and Geometry => $A {X}_{4} {E}_{0}$

#### Explanation:

From the formula given $H C C {l}_{3}$ there are 4 bonded pairs of electrons attached to the central element carbon (C) and zero (0) non-bonded pairs of electrons.

Non-bonded pairs = $\frac{\text{Valence" "Electrons" - "Substrate" "Electrons}}{2}$

Valence electrons = 1H + 1C +3Cl = 1(1) + 1(4) + 3(7) = 26

Substrate electrons = 1H + 3Cl = 1(2) + 3(8) = 26

Non-bonded ${e}^{-}$ pairs = $\frac{{V}_{e} - {S}_{e}}{2}$ = $\frac{26 - 26}{2}$ = 0

Bonded ${e}^{-}$ Pairs = number of substates attached to the central element = 4

$\therefore$ Parent and Structural Geometry = $A {X}_{4} {E}_{0}$ => Tetrahedral Geometry