What is the moment of force about point O? (Refer to the image below)

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1 Answer

Answer:

#2490.9696\ \text{lb feet}#

Explanation:

Resolving the force of #600\ lb# into parallel & vertical components with respect to the axis of given rod/link.

The total torque about the point O in anticlockwise direction,

#=(600\ lb)\cos(30^\circ+20^\circ)\times (0.5\ \text{feet})+(600\ lb)\sin(30^\circ+20^\circ)\times (5\ \text{feet})#

#=600(0.5\cos50^\circ+5\sin50^\circ)\ \text{lb feet}#

#=2490.9696\ \text{lb feet}#