Question

What is the net area between `f(x) = sinx` and the x-axis over `x in [0, 3pi ]`?

Answer 1

2 units

Explanation:

The net area from 0 to `3pi` would be equal to the area between 0 to `pi` which would be

`int_0^pi sinx dx` = `-[cos x]_0^pi` = -[-1-1]=2