# What is the net area between f(x) = x^2+1/x  and the x-axis over x in [2, 4 ]?

$A = {\int}_{2}^{4} \left({x}^{2} + \frac{1}{x}\right) \mathrm{dx} = {\left[{x}^{3} / 3 + \ln x\right]}_{2}^{4} = \frac{56}{3} + \ln 2 = 19.36$