Question

What is the net area between `f(x) = x^2-x+2` and the x-axis over `x in [1, 2 ]`?

Answer 1

Area = `17/6`

Explanation:

Area of curve or function f(x) is given by the integral:
`A = int_a^b f(x) dx; x: x in [a, b]`
for `int_1^2 (x^2 - x +2)dx = [1/3x^3-1/2x^2+2x]_1^2`
Area = `17/6`